Base | Representation |
---|---|
bin | 101101011111110111100001… |
… | …010110110111011010101111 |
3 | 222020111120021021121211020122 |
4 | 231133313201112313122233 |
5 | 202211432410112033403 |
6 | 1545325332333235155 |
7 | 60101615255015036 |
oct | 5537674126673257 |
9 | 866446237554218 |
10 | 200102012221103 |
11 | 588388722829a3 |
12 | 1a53913b032abb |
13 | 87867009344a5 |
14 | 375adbc00171d |
15 | 18201a4ca2838 |
hex | b5fde15b76af |
200102012221103 has 2 divisors, whose sum is σ = 200102012221104. Its totient is φ = 200102012221102.
The previous prime is 200102012221051. The next prime is 200102012221129. The reversal of 200102012221103 is 301122210201002.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 200102012221103 - 224 = 200101995443887 is a prime.
It is a super-3 number, since 3×2001020122211033 (a number of 44 digits) contains 333 as substring.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (200102012221303) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 100051006110551 + 100051006110552.
It is an arithmetic number, because the mean of its divisors is an integer number (100051006110552).
Almost surely, 2200102012221103 is an apocalyptic number.
200102012221103 is a deficient number, since it is larger than the sum of its proper divisors (1).
200102012221103 is an equidigital number, since it uses as much as digits as its factorization.
200102012221103 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 96, while the sum is 17.
Adding to 200102012221103 its reverse (301122210201002), we get a palindrome (501224222422105).
The spelling of 200102012221103 in words is "two hundred trillion, one hundred two billion, twelve million, two hundred twenty-one thousand, one hundred three".
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