200110021217 has 2 divisors, whose sum is σ = 200110021218. Its totient is φ = 200110021216.

The previous prime is 200110021171. The next prime is 200110021219. The reversal of 200110021217 is 712120011002.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 195236724736 + 4873296481 = 441856^2 + 69809^2 .

It is a cyclic number.

It is not a de Polignac number, because 200110021217 - 2¹⁶ = 200109955681 is a prime.

It is a super-2 number, since 2×200110021217² (a number of 23 digits) contains 22 as substring.

Together with 200110021219, it forms a pair of twin primes.

It is a Chen prime.

It is a junction number, because it is equal to n+sod(n) for n = 200110021195 and 200110021204.

It is not a weakly prime, because it can be changed into another prime (200110021219) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 100055010608 + 100055010609.

It is an arithmetic number, because the mean of its divisors is an integer number (100055010609).

Almost surely, 2^200110021217 is an apocalyptic number.

It is an amenable number.

200110021217 is a deficient number, since it is larger than the sum of its proper divisors (1).

200110021217 is an equidigital number, since it uses as much as digits as its factorization.

200110021217 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 56, while the sum is 17.

Adding to 200110021217 its reverse (712120011002), we get a palindrome (912230032219).

The spelling of 200110021217 in words is "two hundred billion, one hundred ten million, twenty-one thousand, two hundred seventeen".