200110134113 has 4 divisors (see below), whose sum is σ = 200793104148. Its totient is φ = 199427164080.

The previous prime is 200110134047. The next prime is 200110134143. The reversal of 200110134113 is 311431011002.

It is a semiprime because it is the product of two primes, and also an emirpimes, since its reverse is a distinct semiprime: 311431011002 = 2 ⋅155715505501.

It can be written as a sum of positive squares in 2 ways, for example, as 96900218944 + 103209915169 = 311288^2 + 321263^2 .

It is a cyclic number.

It is not a de Polignac number, because 200110134113 - 2⁸ = 200110133857 is a prime.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 200110134091 and 200110134100.

It is not an unprimeable number, because it can be changed into a prime (200110134143) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 341484578 + ... + 341485163.

It is an arithmetic number, because the mean of its divisors is an integer number (50198276037).

Almost surely, 2^200110134113 is an apocalyptic number.

It is an amenable number.

200110134113 is a deficient number, since it is larger than the sum of its proper divisors (682970035).

200110134113 is an equidigital number, since it uses as much as digits as its factorization.

200110134113 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 682970034.

The product of its (nonzero) digits is 72, while the sum is 17.

Adding to 200110134113 its reverse (311431011002), we get a palindrome (511541145115).

The spelling of 200110134113 in words is "two hundred billion, one hundred ten million, one hundred thirty-four thousand, one hundred thirteen".