200111000051 has 2 divisors, whose sum is σ = 200111000052. Its totient is φ = 200111000050.

The previous prime is 200110999973. The next prime is 200111000053. The reversal of 200111000051 is 150000111002.

It is a strong prime.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-200111000051 is a prime.

It is a super-2 number, since 2×200111000051² (a number of 23 digits) contains 22 as substring.

It is a Sophie Germain prime.

Together with 200111000053, it forms a pair of twin primes.

It is a Chen prime.

It is a junction number, because it is equal to n+sod(n) for n = 200110999996 and 200111000041.

It is not a weakly prime, because it can be changed into another prime (200111000053) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 100055500025 + 100055500026.

It is an arithmetic number, because the mean of its divisors is an integer number (100055500026).

Almost surely, 2^200111000051 is an apocalyptic number.

200111000051 is a deficient number, since it is larger than the sum of its proper divisors (1).

200111000051 is an equidigital number, since it uses as much as digits as its factorization.

200111000051 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 10, while the sum is 11.

Adding to 200111000051 its reverse (150000111002), we get a palindrome (350111111053).

The spelling of 200111000051 in words is "two hundred billion, one hundred eleven million, fifty-one", and thus it is an aban number.