Base | Representation |
---|---|
bin | 11101000111101011100… |
… | …101010010001010100011 |
3 | 21002022012221200002011222 |
4 | 131013223211102022203 |
5 | 230241234211242011 |
6 | 4131144231325255 |
7 | 264401266103024 |
oct | 35075345221243 |
9 | 7068187602158 |
10 | 2001112212131 |
11 | 70173774726a |
12 | 2839b452082b |
13 | 11691cacc766 |
14 | 6cbd648ac4b |
15 | 370c0976ddb |
hex | 1d1eb9522a3 |
2001112212131 has 2 divisors, whose sum is σ = 2001112212132. Its totient is φ = 2001112212130.
The previous prime is 2001112212109. The next prime is 2001112212247. The reversal of 2001112212131 is 1312122111002.
It is a happy number.
It is a weak prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-2001112212131 is a prime.
It is a super-2 number, since 2×20011122121312 (a number of 25 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (2001112214131) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1000556106065 + 1000556106066.
It is an arithmetic number, because the mean of its divisors is an integer number (1000556106066).
Almost surely, 22001112212131 is an apocalyptic number.
2001112212131 is a deficient number, since it is larger than the sum of its proper divisors (1).
2001112212131 is an equidigital number, since it uses as much as digits as its factorization.
2001112212131 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 48, while the sum is 17.
Adding to 2001112212131 its reverse (1312122111002), we get a palindrome (3313234323133).
The spelling of 2001112212131 in words is "two trillion, one billion, one hundred twelve million, two hundred twelve thousand, one hundred thirty-one".
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