20011210196903 has 2 divisors, whose sum is σ = 20011210196904. Its totient is φ = 20011210196902.

The previous prime is 20011210196891. The next prime is 20011210196933. The reversal of 20011210196903 is 30969101211002.

It is a happy number.

It is a weak prime.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-20011210196903 is a prime.

It is a super-3 number, since 3×20011210196903³ (a number of 41 digits) contains 333 as substring.

It is a Sophie Germain prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (20011210196933) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 10005605098451 + 10005605098452.

It is an arithmetic number, because the mean of its divisors is an integer number (10005605098452).

Almost surely, 2^{20011210196903} is an apocalyptic number.

20011210196903 is a deficient number, since it is larger than the sum of its proper divisors (1).

20011210196903 is an equidigital number, since it uses as much as digits as its factorization.

20011210196903 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 5832, while the sum is 35.

The spelling of 20011210196903 in words is "twenty trillion, eleven billion, two hundred ten million, one hundred ninety-six thousand, nine hundred three".