Base | Representation |
---|---|
bin | 10010101000110000… |
… | …101101110101011010 |
3 | 1220122121121220101112 |
4 | 102220300231311122 |
5 | 311440332241442 |
6 | 13105405420322 |
7 | 1305616332206 |
oct | 225060556532 |
9 | 56577556345 |
10 | 20011212122 |
11 | 8539897940 |
12 | 3a6586a6a2 |
13 | 1b6bb02125 |
14 | d7b9a3b06 |
15 | 7c1c33082 |
hex | 4a8c2dd5a |
20011212122 has 8 divisors (see below), whose sum is σ = 32745619872. Its totient is φ = 9096005500.
The previous prime is 20011212083. The next prime is 20011212191. The reversal of 20011212122 is 22121211002.
It is a sphenic number, since it is the product of 3 distinct primes.
It is a super-2 number, since 2×200112121222 (a number of 21 digits) contains 22 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 20011212097 and 20011212106.
It is an unprimeable number.
It is a pernicious number, because its binary representation contains a prime number (17) of ones.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 454800254 + ... + 454800297.
It is an arithmetic number, because the mean of its divisors is an integer number (4093202484).
Almost surely, 220011212122 is an apocalyptic number.
20011212122 is a gapful number since it is divisible by the number (22) formed by its first and last digit.
20011212122 is a deficient number, since it is larger than the sum of its proper divisors (12734407750).
20011212122 is a wasteful number, since it uses less digits than its factorization.
20011212122 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 909600564.
The product of its (nonzero) digits is 32, while the sum is 14.
Adding to 20011212122 its reverse (22121211002), we get a palindrome (42132423124).
The spelling of 20011212122 in words is "twenty billion, eleven million, two hundred twelve thousand, one hundred twenty-two".
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