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20011220023 = 163122768221
BaseRepresentation
bin10010101000110000…
…101111110000110111
31220122121122022020011
4102220300233300313
5311440333020043
613105405521051
71305616364224
oct225060576067
956577568204
1020011220023
1185398a2873
123a65873187
131b6bb058c2
14d7b9a694b
157c1c3559d
hex4a8c2fc37

20011220023 has 4 divisors (see below), whose sum is σ = 20133988408. Its totient is φ = 19888451640.

The previous prime is 20011219997. The next prime is 20011220027. The reversal of 20011220023 is 32002211002.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 20011220023 - 29 = 20011219511 is a prime.

It is a super-2 number, since 2×200112200232 (a number of 21 digits) contains 22 as substring.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 20011219985 and 20011220012.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (20011220027) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 61383948 + ... + 61384273.

It is an arithmetic number, because the mean of its divisors is an integer number (5033497102).

Almost surely, 220011220023 is an apocalyptic number.

20011220023 is a deficient number, since it is larger than the sum of its proper divisors (122768385).

20011220023 is a wasteful number, since it uses less digits than its factorization.

20011220023 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 122768384.

The product of its (nonzero) digits is 48, while the sum is 13.

Adding to 20011220023 its reverse (32002211002), we get a palindrome (52013431025).

The spelling of 20011220023 in words is "twenty billion, eleven million, two hundred twenty thousand, twenty-three".

Divisors: 1 163 122768221 20011220023