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20011313303 = 97683302053
BaseRepresentation
bin10010101000110001…
…000110100010010111
31220122121211001011222
4102220301012202113
5311440344011203
613105411520555
71305620233202
oct225061064227
956577731158
1020011313303
118539956963
123a658b915b
131b6bb391b7
14d7b9cc939
157c1c53038
hex4a8c46897

20011313303 has 8 divisors (see below), whose sum is σ = 20247283728. Its totient is φ = 19775948544.

The previous prime is 20011313299. The next prime is 20011313339. The reversal of 20011313303 is 30331311002.

It is a sphenic number, since it is the product of 3 distinct primes.

It is a cyclic number.

It is not a de Polignac number, because 20011313303 - 22 = 20011313299 is a prime.

It is a super-2 number, since 2×200113133032 (a number of 21 digits) contains 22 as substring.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (20011313353) by changing a digit.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 84776 + ... + 217277.

It is an arithmetic number, because the mean of its divisors is an integer number (2530910466).

Almost surely, 220011313303 is an apocalyptic number.

20011313303 is a deficient number, since it is larger than the sum of its proper divisors (235970425).

20011313303 is an equidigital number, since it uses as much as digits as its factorization.

20011313303 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 302833.

The product of its (nonzero) digits is 162, while the sum is 17.

Adding to 20011313303 its reverse (30331311002), we get a palindrome (50342624305).

The spelling of 20011313303 in words is "twenty billion, eleven million, three hundred thirteen thousand, three hundred three".

Divisors: 1 97 683 66251 302053 29299141 206302199 20011313303