20011320013 has 4 divisors (see below), whose sum is σ = 20022935968. Its totient is φ = 19999704060.

The previous prime is 20011319987. The next prime is 20011320029. The reversal of 20011320013 is 31002311002.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 20011320013 - 2¹³ = 20011311821 is a prime.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 20011319975 and 20011320002.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (20011320113) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 5805393 + ... + 5808838.

It is an arithmetic number, because the mean of its divisors is an integer number (5005733992).

Almost surely, 2^20011320013 is an apocalyptic number.

It is an amenable number.

20011320013 is a deficient number, since it is larger than the sum of its proper divisors (11615955).

20011320013 is a wasteful number, since it uses less digits than its factorization.

20011320013 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 11615954.

The product of its (nonzero) digits is 36, while the sum is 13.

Adding to 20011320013 its reverse (31002311002), we get a palindrome (51013631015).

The spelling of 20011320013 in words is "twenty billion, eleven million, three hundred twenty thousand, thirteen".