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2001132437 is a prime number
BaseRepresentation
bin111011101000110…
…1101101110010101
312011110111001122012
41313101231232111
513044242214222
6530323114005
7100406226233
oct16721555625
95143431565
102001132437
11937650467
1247a212905
1325b782945
1414dab1953
15baa381e2
hex7746db95

2001132437 has 2 divisors, whose sum is σ = 2001132438. Its totient is φ = 2001132436.

The previous prime is 2001132391. The next prime is 2001132467. The reversal of 2001132437 is 7342311002.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 2001130756 + 1681 = 44734^2 + 41^2 .

It is a cyclic number.

It is not a de Polignac number, because 2001132437 - 224 = 1984355221 is a prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (2001132467) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1000566218 + 1000566219.

It is an arithmetic number, because the mean of its divisors is an integer number (1000566219).

Almost surely, 22001132437 is an apocalyptic number.

It is an amenable number.

2001132437 is a deficient number, since it is larger than the sum of its proper divisors (1).

2001132437 is an equidigital number, since it uses as much as digits as its factorization.

2001132437 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 1008, while the sum is 23.

The square root of 2001132437 is about 44734.0187888368. The cubic root of 2001132437 is about 1260.1588018963.

Adding to 2001132437 its reverse (7342311002), we get a palindrome (9343443439).

The spelling of 2001132437 in words is "two billion, one million, one hundred thirty-two thousand, four hundred thirty-seven".