200114104413 has 4 divisors (see below), whose sum is σ = 266818805888. Its totient is φ = 133409402940.

The previous prime is 200114104409. The next prime is 200114104439. The reversal of 200114104413 is 314401411002.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is not a de Polignac number, because 200114104413 - 2² = 200114104409 is a prime.

It is a Duffinian number.

It is a Curzon number.

It is a self number, because there is not a number n which added to its sum of digits gives 200114104413.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (200114104013) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 33352350733 + ... + 33352350738.

It is an arithmetic number, because the mean of its divisors is an integer number (66704701472).

Almost surely, 2^200114104413 is an apocalyptic number.

It is an amenable number.

200114104413 is a deficient number, since it is larger than the sum of its proper divisors (66704701475).

200114104413 is an equidigital number, since it uses as much as digits as its factorization.

200114104413 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 66704701474.

The product of its (nonzero) digits is 384, while the sum is 21.

Adding to 200114104413 its reverse (314401411002), we get a palindrome (514515515415).

The spelling of 200114104413 in words is "two hundred billion, one hundred fourteen million, one hundred four thousand, four hundred thirteen".