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2001142201300 = 22521121916771279
BaseRepresentation
bin11101000111101101010…
…111101011101111010100
321002022022001002200120221
4131013231113223233110
5230241314400420200
64131151222204124
7264402112025014
oct35075527535724
97068261080527
102001142201300
1170175266a600
12283a02583644
1311692609c828
146cbda455c44
15370c33ec91a
hex1d1ed5ebbd4

2001142201300 has 216 divisors, whose sum is σ = 4808972206080. Its totient is φ = 722243808000.

The previous prime is 2001142201271. The next prime is 2001142201313. The reversal of 2001142201300 is 31022411002.

It is a congruent number.

It is an unprimeable number.

It is a polite number, since it can be written in 71 ways as a sum of consecutive naturals, for example, 1564614061 + ... + 1564615339.

Almost surely, 22001142201300 is an apocalyptic number.

2001142201300 is a gapful number since it is divisible by the number (20) formed by its first and last digit.

It is an amenable number.

It is a practical number, because each smaller number is the sum of distinct divisors of 2001142201300, and also a Zumkeller number, because its divisors can be partitioned in two sets with the same sum (2404486103040).

2001142201300 is an abundant number, since it is smaller than the sum of its proper divisors (2807830004780).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

2001142201300 is a wasteful number, since it uses less digits than its factorization.

2001142201300 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 2183 (or 2165 counting only the distinct ones).

The product of its (nonzero) digits is 96, while the sum is 16.

Adding to 2001142201300 its reverse (31022411002), we get a palindrome (2032164612302).

The spelling of 2001142201300 in words is "two trillion, one billion, one hundred forty-two million, two hundred one thousand, three hundred".