Base | Representation |
---|---|
bin | 10010101000110001… |
… | …100011100111110001 |
3 | 1220122122001002121012 |
4 | 102220301203213301 |
5 | 311440411314213 |
6 | 13105414240305 |
7 | 1305621240416 |
oct | 225061434761 |
9 | 56578032535 |
10 | 20011432433 |
11 | 8539a28413 |
12 | 3a65956095 |
13 | 1b6bb7b4a5 |
14 | d7ba2010d |
15 | 7c1c784a8 |
hex | 4a8c639f1 |
20011432433 has 8 divisors (see below), whose sum is σ = 20082814752. Its totient is φ = 19940090976.
The previous prime is 20011432423. The next prime is 20011432451. The reversal of 20011432433 is 33423411002.
It is a sphenic number, since it is the product of 3 distinct primes.
It is a cyclic number.
It is not a de Polignac number, because 20011432433 - 26 = 20011432369 is a prime.
It is a Duffinian number.
It is a junction number, because it is equal to n+sod(n) for n = 20011432399 and 20011432408.
It is not an unprimeable number, because it can be changed into a prime (20011432423) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (17) of ones.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 1237466 + ... + 1253532.
It is an arithmetic number, because the mean of its divisors is an integer number (2510351844).
Almost surely, 220011432433 is an apocalyptic number.
It is an amenable number.
20011432433 is a deficient number, since it is larger than the sum of its proper divisors (71382319).
20011432433 is a wasteful number, since it uses less digits than its factorization.
20011432433 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 20431.
The product of its (nonzero) digits is 1728, while the sum is 23.
Adding to 20011432433 its reverse (33423411002), we get a palindrome (53434843435).
The spelling of 20011432433 in words is "twenty billion, eleven million, four hundred thirty-two thousand, four hundred thirty-three".
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