200120130013 has 2 divisors, whose sum is σ = 200120130014. Its totient is φ = 200120130012.

The previous prime is 200120129983. The next prime is 200120130073. The reversal of 200120130013 is 310031021002.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 100297623204 + 99822506809 = 316698^2 + 315947^2 .

It is a cyclic number.

It is not a de Polignac number, because 200120130013 - 2⁵ = 200120129981 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 200120129975 and 200120130002.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (200120130073) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 100060065006 + 100060065007.

It is an arithmetic number, because the mean of its divisors is an integer number (100060065007).

Almost surely, 2^200120130013 is an apocalyptic number.

It is an amenable number.

200120130013 is a deficient number, since it is larger than the sum of its proper divisors (1).

200120130013 is an equidigital number, since it uses as much as digits as its factorization.

200120130013 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 36, while the sum is 13.

Adding to 200120130013 its reverse (310031021002), we get a palindrome (510151151015).

The spelling of 200120130013 in words is "two hundred billion, one hundred twenty million, one hundred thirty thousand, thirteen".