20012030004111 has 4 divisors (see below), whose sum is σ = 26682706672152. Its totient is φ = 13341353336072.

The previous prime is 20012030004047. The next prime is 20012030004149. The reversal of 20012030004111 is 11140003021002.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 20012030004111 - 2⁶ = 20012030004047 is a prime.

It is a super-3 number, since 3×20012030004111³ (a number of 41 digits) contains 333 as substring.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (20012030704111) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 3335338334016 + ... + 3335338334021.

It is an arithmetic number, because the mean of its divisors is an integer number (6670676668038).

Almost surely, 2^{20012030004111} is an apocalyptic number.

20012030004111 is a deficient number, since it is larger than the sum of its proper divisors (6670676668041).

20012030004111 is an equidigital number, since it uses as much as digits as its factorization.

20012030004111 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 6670676668040.

The product of its (nonzero) digits is 48, while the sum is 15.

Adding to 20012030004111 its reverse (11140003021002), we get a palindrome (31152033025113).

The spelling of 20012030004111 in words is "twenty trillion, twelve billion, thirty million, four thousand, one hundred eleven".