Base | Representation |
---|---|
bin | 1001000110011011011101… |
… | …10100111011010001101111 |
3 | 2121212010202111022212021110 |
4 | 10203031232310323101233 |
5 | 10110334301133000421 |
6 | 110321234244203103 |
7 | 4133553535230360 |
oct | 443155664732157 |
9 | 77763674285243 |
10 | 20012112000111 |
11 | 64160a8566a90 |
12 | 22b2593999493 |
13 | b221987010ca |
14 | 4d283cab1b67 |
15 | 24a86337ba76 |
hex | 12336ed3b46f |
20012112000111 has 32 divisors (see below), whose sum is σ = 33272708617728. Its totient is φ = 10394083232640.
The previous prime is 20012112000061. The next prime is 20012112000121. The reversal of 20012112000111 is 11100021121002.
It is not a de Polignac number, because 20012112000111 - 29 = 20012111999599 is a prime.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (20012112000121) by changing a digit.
It is a polite number, since it can be written in 31 ways as a sum of consecutive naturals, for example, 6256120 + ... + 8897373.
It is an arithmetic number, because the mean of its divisors is an integer number (1039772144304).
Almost surely, 220012112000111 is an apocalyptic number.
20012112000111 is a gapful number since it is divisible by the number (21) formed by its first and last digit.
20012112000111 is a deficient number, since it is larger than the sum of its proper divisors (13260596617617).
20012112000111 is a wasteful number, since it uses less digits than its factorization.
20012112000111 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 15159231.
The product of its (nonzero) digits is 8, while the sum is 12.
Adding to 20012112000111 its reverse (11100021121002), we get a palindrome (31112133121113).
It can be divided in two parts, 2001 and 2112000111, that added together give a palindrome (2112002112).
The spelling of 20012112000111 in words is "twenty trillion, twelve billion, one hundred twelve million, one hundred eleven", and thus it is an aban number.
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