Base | Representation |
---|---|
bin | 10010101000110100… |
… | …001001100010010001 |
3 | 1220122200022121210222 |
4 | 102220310021202101 |
5 | 311441100041032 |
6 | 13105441002425 |
7 | 1305630100622 |
oct | 225064114221 |
9 | 56580277728 |
10 | 20012112017 |
11 | 853a351a57 |
12 | 3a66023415 |
13 | 1b6c058901 |
14 | d7bb59a49 |
15 | 7c1d5ea12 |
hex | 4a8d09891 |
20012112017 has 2 divisors, whose sum is σ = 20012112018. Its totient is φ = 20012112016.
The previous prime is 20012111971. The next prime is 20012112053. The reversal of 20012112017 is 71021121002.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 19913725456 + 98386561 = 141116^2 + 9919^2 .
It is a cyclic number.
It is not a de Polignac number, because 20012112017 - 214 = 20012095633 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 20012111986 and 20012112004.
It is not a weakly prime, because it can be changed into another prime (20012112097) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (13) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 10006056008 + 10006056009.
It is an arithmetic number, because the mean of its divisors is an integer number (10006056009).
Almost surely, 220012112017 is an apocalyptic number.
It is an amenable number.
20012112017 is a deficient number, since it is larger than the sum of its proper divisors (1).
20012112017 is an equidigital number, since it uses as much as digits as its factorization.
20012112017 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 56, while the sum is 17.
Adding to 20012112017 its reverse (71021121002), we get a palindrome (91033233019).
The spelling of 20012112017 in words is "twenty billion, twelve million, one hundred twelve thousand, seventeen".
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