Base | Representation |
---|---|
bin | 1001000110011011101000… |
… | …00101011101101000011011 |
3 | 2121212010222122022221212121 |
4 | 10203031310011131220123 |
5 | 10110334441224034321 |
6 | 110321251115122111 |
7 | 4133555656133632 |
oct | 443156405355033 |
9 | 77763878287777 |
10 | 20012200221211 |
11 | 6416143342890 |
12 | 22b25b9443337 |
13 | b221b0a7c443 |
14 | 4d284a6b8519 |
15 | 24a86aea6441 |
hex | 12337415da1b |
20012200221211 has 4 divisors (see below), whose sum is σ = 21831491150424. Its totient is φ = 18192909292000.
The previous prime is 20012200221191. The next prime is 20012200221217. The reversal of 20012200221211 is 11212200221002.
It is a happy number.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 20012200221211 - 211 = 20012200219163 is a prime.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (20012200221217) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 909645464590 + ... + 909645464611.
It is an arithmetic number, because the mean of its divisors is an integer number (5457872787606).
Almost surely, 220012200221211 is an apocalyptic number.
20012200221211 is a deficient number, since it is larger than the sum of its proper divisors (1819290929213).
20012200221211 is a wasteful number, since it uses less digits than its factorization.
20012200221211 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 1819290929212.
The product of its (nonzero) digits is 64, while the sum is 16.
Adding to 20012200221211 its reverse (11212200221002), we get a palindrome (31224400442213).
The spelling of 20012200221211 in words is "twenty trillion, twelve billion, two hundred million, two hundred twenty-one thousand, two hundred eleven".
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