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20012220122011 = 131539401547847
BaseRepresentation
bin1001000110011011101010…
…10001011000001110011011
32121212011001000210000122021
410203031311101120032123
510110340011322401021
6110321253105435311
74133556320240515
oct443156521301633
977764030700567
1020012220122011
1164161535a5627
1222b260403bb37
13b221b4c29670
144d284d1b8bb5
1524a86cad7c41
hex12337545839b

20012220122011 has 4 divisors (see below), whose sum is σ = 21551621669872. Its totient is φ = 18472818574152.

The previous prime is 20012220122009. The next prime is 20012220122039. The reversal of 20012220122011 is 11022102221002.

It is a happy number.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 20012220122011 - 21 = 20012220122009 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (20012220122611) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 769700773911 + ... + 769700773936.

It is an arithmetic number, because the mean of its divisors is an integer number (5387905417468).

Almost surely, 220012220122011 is an apocalyptic number.

20012220122011 is a deficient number, since it is larger than the sum of its proper divisors (1539401547861).

20012220122011 is a wasteful number, since it uses less digits than its factorization.

20012220122011 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 1539401547860.

The product of its (nonzero) digits is 64, while the sum is 16.

Adding to 20012220122011 its reverse (11022102221002), we get a palindrome (31034322343013).

The spelling of 20012220122011 in words is "twenty trillion, twelve billion, two hundred twenty million, one hundred twenty-two thousand, eleven".

Divisors: 1 13 1539401547847 20012220122011