Base | Representation |
---|---|
bin | 11101000111110010101… |
… | …110010001111101101001 |
3 | 21002022112022002111111022 |
4 | 131013302232101331221 |
5 | 230242010343323423 |
6 | 4131204151142225 |
7 | 264404252266136 |
oct | 35076256217551 |
9 | 7068468074438 |
10 | 2001232011113 |
11 | 701799330a95 |
12 | 283a28674975 |
13 | 11693b88602a |
14 | 6cc0835358d |
15 | 370cb23cdc8 |
hex | 1d1f2b91f69 |
2001232011113 has 2 divisors, whose sum is σ = 2001232011114. Its totient is φ = 2001232011112.
The previous prime is 2001232011101. The next prime is 2001232011179. The reversal of 2001232011113 is 3111102321002.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 1502418935824 + 498813075289 = 1225732^2 + 706267^2 .
It is a cyclic number.
It is not a de Polignac number, because 2001232011113 - 218 = 2001231748969 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 2001232011091 and 2001232011100.
It is not a weakly prime, because it can be changed into another prime (2001232011613) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1000616005556 + 1000616005557.
It is an arithmetic number, because the mean of its divisors is an integer number (1000616005557).
Almost surely, 22001232011113 is an apocalyptic number.
It is an amenable number.
2001232011113 is a deficient number, since it is larger than the sum of its proper divisors (1).
2001232011113 is an equidigital number, since it uses as much as digits as its factorization.
2001232011113 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 72, while the sum is 17.
Adding to 2001232011113 its reverse (3111102321002), we get a palindrome (5112334332115).
The spelling of 2001232011113 in words is "two trillion, one billion, two hundred thirty-two million, eleven thousand, one hundred thirteen".
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