Base | Representation |
---|---|
bin | 1011101001100010111… |
… | …1010011000100001111 |
3 | 201010120110211202122221 |
4 | 2322120233103010033 |
5 | 11234332021000221 |
6 | 231534450320211 |
7 | 20313301461331 |
oct | 2723057230417 |
9 | 633513752587 |
10 | 200131031311 |
11 | 77969827a42 |
12 | 32953589067 |
13 | 15b455091b3 |
14 | 998766d451 |
15 | 5314c08541 |
hex | 2e98bd310f |
200131031311 has 2 divisors, whose sum is σ = 200131031312. Its totient is φ = 200131031310.
The previous prime is 200131031291. The next prime is 200131031327. The reversal of 200131031311 is 113130131002.
It is an a-pointer prime, because the next prime (200131031327) can be obtained adding 200131031311 to its sum of digits (16).
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 200131031311 - 229 = 199594160399 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (200131031381) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 100065515655 + 100065515656.
It is an arithmetic number, because the mean of its divisors is an integer number (100065515656).
Almost surely, 2200131031311 is an apocalyptic number.
200131031311 is a deficient number, since it is larger than the sum of its proper divisors (1).
200131031311 is an equidigital number, since it uses as much as digits as its factorization.
200131031311 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 54, while the sum is 16.
Adding to 200131031311 its reverse (113130131002), we get a palindrome (313261162313).
The spelling of 200131031311 in words is "two hundred billion, one hundred thirty-one million, thirty-one thousand, three hundred eleven".
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