Base | Representation |
---|---|
bin | 1001000110011101010110… |
… | …01011100010110000010111 |
3 | 2121212020101001122022222112 |
4 | 10203032223023202300113 |
5 | 10110343334341440233 |
6 | 110321522535021235 |
7 | 4133620611660602 |
oct | 443165313426027 |
9 | 77766331568875 |
10 | 20013124561943 |
11 | 641657808a747 |
12 | 22b2816b0a81b |
13 | b222ca418c16 |
14 | 4d28d736d339 |
15 | 24a8c21e0048 |
hex | 1233ab2e2c17 |
20013124561943 has 2 divisors, whose sum is σ = 20013124561944. Its totient is φ = 20013124561942.
The previous prime is 20013124561921. The next prime is 20013124562059. The reversal of 20013124561943 is 34916542131002.
It is a happy number.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 20013124561943 - 28 = 20013124561687 is a prime.
It is a self number, because there is not a number n which added to its sum of digits gives 20013124561943.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (20013124561343) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 10006562280971 + 10006562280972.
It is an arithmetic number, because the mean of its divisors is an integer number (10006562280972).
Almost surely, 220013124561943 is an apocalyptic number.
20013124561943 is a deficient number, since it is larger than the sum of its proper divisors (1).
20013124561943 is an equidigital number, since it uses as much as digits as its factorization.
20013124561943 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 155520, while the sum is 41.
Adding to 20013124561943 its reverse (34916542131002), we get a palindrome (54929666692945).
The spelling of 20013124561943 in words is "twenty trillion, thirteen billion, one hundred twenty-four million, five hundred sixty-one thousand, nine hundred forty-three".
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