Base | Representation |
---|---|
bin | 11101000111110111100… |
… | …011111111110000111011 |
3 | 21002022201221212101100222 |
4 | 131013313203333300323 |
5 | 230242142134414321 |
6 | 4131220211250255 |
7 | 264406256350022 |
oct | 35076743776073 |
9 | 7068657771328 |
10 | 2001313201211 |
11 | 701830145345 |
12 | 283a4b8a998b |
13 | 116952641ccc |
14 | 6cc150498b9 |
15 | 370d34293ab |
hex | 1d1f78ffc3b |
2001313201211 has 4 divisors (see below), whose sum is σ = 2001335626152. Its totient is φ = 2001290776272.
The previous prime is 2001313201187. The next prime is 2001313201213. The reversal of 2001313201211 is 1121023131002.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-2001313201211 is a prime.
It is a Duffinian number.
It is a self number, because there is not a number n which added to its sum of digits gives 2001313201211.
It is not an unprimeable number, because it can be changed into a prime (2001313201213) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 11078066 + ... + 11257271.
It is an arithmetic number, because the mean of its divisors is an integer number (500333906538).
Almost surely, 22001313201211 is an apocalyptic number.
2001313201211 is a deficient number, since it is larger than the sum of its proper divisors (22424941).
2001313201211 is an equidigital number, since it uses as much as digits as its factorization.
2001313201211 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 22424940.
The product of its (nonzero) digits is 72, while the sum is 17.
Adding to 2001313201211 its reverse (1121023131002), we get a palindrome (3122336332213).
The spelling of 2001313201211 in words is "two trillion, one billion, three hundred thirteen million, two hundred one thousand, two hundred eleven".
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