200131411 has 4 divisors (see below), whose sum is σ = 202664800. Its totient is φ = 197598024.

The previous prime is 200131403. The next prime is 200131457. The reversal of 200131411 is 114131002.

It is a semiprime because it is the product of two primes, and also an emirpimes, since its reverse is a distinct semiprime: 114131002 = 2 ⋅57065501.

It is a cyclic number.

It is not a de Polignac number, because 200131411 - 2³ = 200131403 is a prime.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 200131391 and 200131400.

It is not an unprimeable number, because it can be changed into a prime (200131111) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 1266576 + ... + 1266733.

It is an arithmetic number, because the mean of its divisors is an integer number (50666200).

Almost surely, 2^200131411 is an apocalyptic number.

200131411 is a deficient number, since it is larger than the sum of its proper divisors (2533389).

200131411 is an equidigital number, since it uses as much as digits as its factorization.

200131411 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 2533388.

The product of its (nonzero) digits is 24, while the sum is 13.

The square root of 200131411 is about 14146.7809412601. The cubic root of 200131411 is about 584.9316022987.

Adding to 200131411 its reverse (114131002), we get a palindrome (314262413).

The spelling of 200131411 in words is "two hundred million, one hundred thirty-one thousand, four hundred eleven".