Base | Representation |
---|---|
bin | 1011101001100011100… |
… | …0011000010100001111 |
3 | 201010120122022201111201 |
4 | 2322120320120110033 |
5 | 11234333123141421 |
6 | 231535013330331 |
7 | 20313330635413 |
oct | 2723070302417 |
9 | 633518281451 |
10 | 200133412111 |
11 | 77970103746 |
12 | 329543369a7 |
13 | 15b45b60a59 |
14 | 9987accd43 |
15 | 5315028b91 |
hex | 2e98e1850f |
200133412111 has 2 divisors, whose sum is σ = 200133412112. Its totient is φ = 200133412110.
The previous prime is 200133412109. The next prime is 200133412121. The reversal of 200133412111 is 111214331002.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 200133412111 - 21 = 200133412109 is a prime.
It is a super-2 number, since 2×2001334121112 (a number of 23 digits) contains 22 as substring.
Together with 200133412109, it forms a pair of twin primes.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (200133412121) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 100066706055 + 100066706056.
It is an arithmetic number, because the mean of its divisors is an integer number (100066706056).
Almost surely, 2200133412111 is an apocalyptic number.
200133412111 is a deficient number, since it is larger than the sum of its proper divisors (1).
200133412111 is an equidigital number, since it uses as much as digits as its factorization.
200133412111 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 144, while the sum is 19.
Adding to 200133412111 its reverse (111214331002), we get a palindrome (311347743113).
The spelling of 200133412111 in words is "two hundred billion, one hundred thirty-three million, four hundred twelve thousand, one hundred eleven".
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