Base | Representation |
---|---|
bin | 10010101000111001… |
… | …101001111001100101 |
3 | 1220122210000221121221 |
4 | 102220321221321211 |
5 | 311441432232201 |
6 | 13105531540341 |
7 | 1305645261505 |
oct | 225071517145 |
9 | 56583027557 |
10 | 20013555301 |
11 | 8540148353 |
12 | 3a665ba6b1 |
13 | 1b6c44281c |
14 | d7c013a05 |
15 | 7c20474a1 |
hex | 4a8e69e65 |
20013555301 has 2 divisors, whose sum is σ = 20013555302. Its totient is φ = 20013555300.
The previous prime is 20013555299. The next prime is 20013555319. The reversal of 20013555301 is 10355531002.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 16808863201 + 3204692100 = 129649^2 + 56610^2 .
It is a cyclic number.
It is not a de Polignac number, because 20013555301 - 21 = 20013555299 is a prime.
Together with 20013555299, it forms a pair of twin primes.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (20013550301) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 10006777650 + 10006777651.
It is an arithmetic number, because the mean of its divisors is an integer number (10006777651).
Almost surely, 220013555301 is an apocalyptic number.
It is an amenable number.
20013555301 is a deficient number, since it is larger than the sum of its proper divisors (1).
20013555301 is an equidigital number, since it uses as much as digits as its factorization.
20013555301 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 2250, while the sum is 25.
The spelling of 20013555301 in words is "twenty billion, thirteen million, five hundred fifty-five thousand, three hundred one".
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