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20013645038147 is a prime number
BaseRepresentation
bin1001000110011110010100…
…01101000000001001000011
32121212021201100000021002222
410203033022031000021003
510110400421112210042
6110322050330401255
74133636531646125
oct443171215001103
977767640007088
1020013645038147
116416814962172
1222b294129022b
13b223811c00c7
144d2946535215
1524a902c502d2
hex1233ca340243

20013645038147 has 2 divisors, whose sum is σ = 20013645038148. Its totient is φ = 20013645038146.

The previous prime is 20013645038143. The next prime is 20013645038161. The reversal of 20013645038147 is 74183054631002.

It is a happy number.

It is a weak prime.

It is a cyclic number.

It is not a de Polignac number, because 20013645038147 - 22 = 20013645038143 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 20013645038098 and 20013645038107.

It is not a weakly prime, because it can be changed into another prime (20013645038143) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 10006822519073 + 10006822519074.

It is an arithmetic number, because the mean of its divisors is an integer number (10006822519074).

Almost surely, 220013645038147 is an apocalyptic number.

20013645038147 is a deficient number, since it is larger than the sum of its proper divisors (1).

20013645038147 is an equidigital number, since it uses as much as digits as its factorization.

20013645038147 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 483840, while the sum is 44.

Adding to 20013645038147 its reverse (74183054631002), we get a palindrome (94196699669149).

The spelling of 20013645038147 in words is "twenty trillion, thirteen billion, six hundred forty-five million, thirty-eight thousand, one hundred forty-seven".