Base | Representation |
---|---|
bin | 1001000110011110010100… |
… | …01101000000001001000011 |
3 | 2121212021201100000021002222 |
4 | 10203033022031000021003 |
5 | 10110400421112210042 |
6 | 110322050330401255 |
7 | 4133636531646125 |
oct | 443171215001103 |
9 | 77767640007088 |
10 | 20013645038147 |
11 | 6416814962172 |
12 | 22b294129022b |
13 | b223811c00c7 |
14 | 4d2946535215 |
15 | 24a902c502d2 |
hex | 1233ca340243 |
20013645038147 has 2 divisors, whose sum is σ = 20013645038148. Its totient is φ = 20013645038146.
The previous prime is 20013645038143. The next prime is 20013645038161. The reversal of 20013645038147 is 74183054631002.
It is a happy number.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 20013645038147 - 22 = 20013645038143 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 20013645038098 and 20013645038107.
It is not a weakly prime, because it can be changed into another prime (20013645038143) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (17) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 10006822519073 + 10006822519074.
It is an arithmetic number, because the mean of its divisors is an integer number (10006822519074).
Almost surely, 220013645038147 is an apocalyptic number.
20013645038147 is a deficient number, since it is larger than the sum of its proper divisors (1).
20013645038147 is an equidigital number, since it uses as much as digits as its factorization.
20013645038147 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 483840, while the sum is 44.
Adding to 20013645038147 its reverse (74183054631002), we get a palindrome (94196699669149).
The spelling of 20013645038147 in words is "twenty trillion, thirteen billion, six hundred forty-five million, thirty-eight thousand, one hundred forty-seven".
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