Base | Representation |
---|---|
bin | 1001000110011110010101… |
… | …11010101010000001110111 |
3 | 2121212021202011112022012011 |
4 | 10203033022322222001313 |
5 | 10110400432143144244 |
6 | 110322051435105051 |
7 | 4133640035453323 |
oct | 443171272520167 |
9 | 77767664468164 |
10 | 20013657006199 |
11 | 6416820696a1a |
12 | 22b29452a2187 |
13 | b223838206ac |
14 | 4d2947d6c983 |
15 | 24a903d16434 |
hex | 1233caeaa077 |
20013657006199 has 2 divisors, whose sum is σ = 20013657006200. Its totient is φ = 20013657006198.
The previous prime is 20013657006191. The next prime is 20013657006253. The reversal of 20013657006199 is 99160075631002.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 20013657006199 - 23 = 20013657006191 is a prime.
It is a super-3 number, since 3×200136570061993 (a number of 41 digits) contains 333 as substring.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (20013657006191) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 10006828503099 + 10006828503100.
It is an arithmetic number, because the mean of its divisors is an integer number (10006828503100).
Almost surely, 220013657006199 is an apocalyptic number.
20013657006199 is a deficient number, since it is larger than the sum of its proper divisors (1).
20013657006199 is an equidigital number, since it uses as much as digits as its factorization.
20013657006199 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 612360, while the sum is 49.
The spelling of 20013657006199 in words is "twenty trillion, thirteen billion, six hundred fifty-seven million, six thousand, one hundred ninety-nine".
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