Base | Representation |
---|---|
bin | 11101000111111100110… |
… | …110111001111101000111 |
3 | 21002022222011001002002012 |
4 | 131013330312321331013 |
5 | 230242332410403411 |
6 | 4131233103404435 |
7 | 264411415453412 |
oct | 35077466717507 |
9 | 7068864032065 |
10 | 2001402044231 |
11 | 701876306427 |
12 | 283a755b371b |
13 | 116967b7a445 |
14 | 6cc22b74b79 |
15 | 370db12818b |
hex | 1d1fcdb9f47 |
2001402044231 has 2 divisors, whose sum is σ = 2001402044232. Its totient is φ = 2001402044230.
The previous prime is 2001402044183. The next prime is 2001402044249. The reversal of 2001402044231 is 1324402041002.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 2001402044231 - 218 = 2001401782087 is a prime.
It is a super-2 number, since 2×20014020442312 (a number of 25 digits) contains 22 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 2001402044197 and 2001402044206.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (2001402044251) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1000701022115 + 1000701022116.
It is an arithmetic number, because the mean of its divisors is an integer number (1000701022116).
Almost surely, 22001402044231 is an apocalyptic number.
2001402044231 is a deficient number, since it is larger than the sum of its proper divisors (1).
2001402044231 is an equidigital number, since it uses as much as digits as its factorization.
2001402044231 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 1536, while the sum is 23.
Adding to 2001402044231 its reverse (1324402041002), we get a palindrome (3325804085233).
The spelling of 2001402044231 in words is "two trillion, one billion, four hundred two million, forty-four thousand, two hundred thirty-one".
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