20014331101 has 4 divisors (see below), whose sum is σ = 20020859872. Its totient is φ = 20007802332.

The previous prime is 20014331059. The next prime is 20014331191. The reversal of 20014331101 is 10113341002.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4, and also an emirpimes, since its reverse is a distinct semiprime: 10113341002 = 2 ⋅5056670501.

It is a cyclic number.

It is not a de Polignac number, because 20014331101 - 2²³ = 20005942493 is a prime.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (20014331191) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 3259785 + ... + 3265918.

It is an arithmetic number, because the mean of its divisors is an integer number (5005214968).

Almost surely, 2^20014331101 is an apocalyptic number.

It is an amenable number.

20014331101 is a deficient number, since it is larger than the sum of its proper divisors (6528771).

20014331101 is an equidigital number, since it uses as much as digits as its factorization.

20014331101 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 6528770.

The product of its (nonzero) digits is 72, while the sum is 16.

Adding to 20014331101 its reverse (10113341002), we get a palindrome (30127672103).

Subtracting from 20014331101 its reverse (10113341002), we obtain a palindrome (9900990099).

The spelling of 20014331101 in words is "twenty billion, fourteen million, three hundred thirty-one thousand, one hundred one".