20015320153 has 4 divisors (see below), whose sum is σ = 20885551488. Its totient is φ = 19145088820.

The previous prime is 20015320103. The next prime is 20015320201. The reversal of 20015320153 is 35102351002.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 20015320153 - 2²¹ = 20013223001 is a prime.

It is a super-2 number, since 2×20015320153² (a number of 21 digits) contains 22 as substring.

It is not an unprimeable number, because it can be changed into a prime (20015320103) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (13) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 435115633 + ... + 435115678.

It is an arithmetic number, because the mean of its divisors is an integer number (5221387872).

Almost surely, 2^20015320153 is an apocalyptic number.

20015320153 is a gapful number since it is divisible by the number (23) formed by its first and last digit.

It is an amenable number.

20015320153 is a deficient number, since it is larger than the sum of its proper divisors (870231335).

20015320153 is an equidigital number, since it uses as much as digits as its factorization.

20015320153 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 870231334.

The product of its (nonzero) digits is 900, while the sum is 22.

Adding to 20015320153 its reverse (35102351002), we get a palindrome (55117671155).

The spelling of 20015320153 in words is "twenty billion, fifteen million, three hundred twenty thousand, one hundred fifty-three".