Base | Representation |
---|---|
bin | 1001000110101100000001… |
… | …00101111111110100000101 |
3 | 2121212222200220200121010102 |
4 | 10203112000211333310011 |
5 | 10111011002000323023 |
6 | 110325304225133445 |
7 | 4134320021123531 |
oct | 443260045776405 |
9 | 77788626617112 |
10 | 20021000011013 |
11 | 6419949618141 |
12 | 22b425448a285 |
13 | b22c83c00861 |
14 | 4d3043294bc1 |
15 | 24abd37d6628 |
hex | 12358097fd05 |
20021000011013 has 2 divisors, whose sum is σ = 20021000011014. Its totient is φ = 20021000011012.
The previous prime is 20021000010929. The next prime is 20021000011031. The reversal of 20021000011013 is 31011000012002.
Together with next prime (20021000011031) it forms an Ormiston pair, because they use the same digits, order apart.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 17840292145729 + 2180707865284 = 4223777^2 + 1476722^2 .
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-20021000011013 is a prime.
It is a super-2 number, since 2×200210000110132 (a number of 27 digits) contains 22 as substring.
It is a Sophie Germain prime.
It is a Curzon number.
It is a junction number, because it is equal to n+sod(n) for n = 20021000010985 and 20021000011003.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (20021000011093) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 10010500005506 + 10010500005507.
It is an arithmetic number, because the mean of its divisors is an integer number (10010500005507).
Almost surely, 220021000011013 is an apocalyptic number.
It is an amenable number.
20021000011013 is a deficient number, since it is larger than the sum of its proper divisors (1).
20021000011013 is an equidigital number, since it uses as much as digits as its factorization.
20021000011013 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 12, while the sum is 11.
Adding to 20021000011013 its reverse (31011000012002), we get a palindrome (51032000023015).
The spelling of 20021000011013 in words is "twenty trillion, twenty-one billion, eleven thousand, thirteen".
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