Base | Representation |
---|---|
bin | 101101100001011100001011… |
… | …111001110010011010111111 |
3 | 222020212220021010020010022221 |
4 | 231201130023321302122333 |
5 | 202220220241122414101 |
6 | 1545451130021550211 |
7 | 60112462631464225 |
oct | 5541341371623277 |
9 | 866786233203287 |
10 | 200210100201151 |
11 | 5887a699108127 |
12 | 1a556085575367 |
13 | 8793967c7c731 |
14 | 37623132acb15 |
15 | 1822dce0b5aa1 |
hex | b6170be726bf |
200210100201151 has 2 divisors, whose sum is σ = 200210100201152. Its totient is φ = 200210100201150.
The previous prime is 200210100201149. The next prime is 200210100201193. The reversal of 200210100201151 is 151102001012002.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 200210100201151 - 21 = 200210100201149 is a prime.
Together with 200210100201149, it forms a pair of twin primes.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (200210100201101) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 100105050100575 + 100105050100576.
It is an arithmetic number, because the mean of its divisors is an integer number (100105050100576).
Almost surely, 2200210100201151 is an apocalyptic number.
200210100201151 is a deficient number, since it is larger than the sum of its proper divisors (1).
200210100201151 is an equidigital number, since it uses as much as digits as its factorization.
200210100201151 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 40, while the sum is 16.
Adding to 200210100201151 its reverse (151102001012002), we get a palindrome (351312101213153).
The spelling of 200210100201151 in words is "two hundred trillion, two hundred ten billion, one hundred million, two hundred one thousand, one hundred fifty-one".
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