Base | Representation |
---|---|
bin | 11101001000100110100… |
… | …001111110010100011001 |
3 | 21002101202212121212200222 |
4 | 131020212201332110121 |
5 | 230300300401401103 |
6 | 4131430321005425 |
7 | 264434635261025 |
oct | 35104641762431 |
9 | 7071685555628 |
10 | 2002101200153 |
11 | 7020a4a2963a |
12 | 28402b783875 |
13 | 116a49982582 |
14 | 6cc8b96d385 |
15 | 3712c6d0638 |
hex | 1d22687e519 |
2002101200153 has 2 divisors, whose sum is σ = 2002101200154. Its totient is φ = 2002101200152.
The previous prime is 2002101200123. The next prime is 2002101200227. The reversal of 2002101200153 is 3510021012002.
It is a happy number.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 1327030273024 + 675070927129 = 1151968^2 + 821627^2 .
It is a cyclic number.
It is not a de Polignac number, because 2002101200153 - 216 = 2002101134617 is a prime.
It is not a weakly prime, because it can be changed into another prime (2002101200123) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1001050600076 + 1001050600077.
It is an arithmetic number, because the mean of its divisors is an integer number (1001050600077).
Almost surely, 22002101200153 is an apocalyptic number.
It is an amenable number.
2002101200153 is a deficient number, since it is larger than the sum of its proper divisors (1).
2002101200153 is an equidigital number, since it uses as much as digits as its factorization.
2002101200153 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 120, while the sum is 17.
Adding to 2002101200153 its reverse (3510021012002), we get a palindrome (5512122212155).
The spelling of 2002101200153 in words is "two trillion, two billion, one hundred one million, two hundred thousand, one hundred fifty-three".
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