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200210122012110 = 235722371433192617
BaseRepresentation
bin101101100001011100001101…
…001100111111010111001110
3222020212220022122021020100020
4231201130031030333113032
5202220220312213341420
61545451132121243010
760112463315045100
oct5541341514772716
9866786278236306
10200210122012110
115887a6aa455011
121a556090933466
13879396c648222
143762316149570
151822dd0e73340
hexb6170d33f5ce

200210122012110 has 384 divisors, whose sum is σ = 592840259794944. Its totient is φ = 43056240353280.

The previous prime is 200210122012073. The next prime is 200210122012157. The reversal of 200210122012110 is 11210221012002.

It is a super-3 number, since 3×2002101220121103 (a number of 44 digits) contains 333 as substring. Note that it is a super-d number also for d = 2.

It is a Harshad number since it is a multiple of its sum of digits (15).

It is a self number, because there is not a number n which added to its sum of digits gives 200210122012110.

It is a congruent number.

It is an unprimeable number.

It is a polite number, since it can be written in 191 ways as a sum of consecutive naturals, for example, 1039324522 + ... + 1039517138.

It is an arithmetic number, because the mean of its divisors is an integer number (1543854843216).

Almost surely, 2200210122012110 is an apocalyptic number.

It is a practical number, because each smaller number is the sum of distinct divisors of 200210122012110, and also a Zumkeller number, because its divisors can be partitioned in two sets with the same sum (296420129897472).

200210122012110 is an abundant number, since it is smaller than the sum of its proper divisors (392630137782834).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

200210122012110 is a wasteful number, since it uses less digits than its factorization.

200210122012110 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 193168 (or 193161 counting only the distinct ones).

The product of its (nonzero) digits is 32, while the sum is 15.

Adding to 200210122012110 its reverse (11210221012002), we get a palindrome (211420343024112).

The spelling of 200210122012110 in words is "two hundred trillion, two hundred ten billion, one hundred twenty-two million, twelve thousand, one hundred ten".