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2002102011013 = 13154007847001
BaseRepresentation
bin11101001000100110100…
…101000100010010000101
321002101202221011001222211
4131020212211010102011
5230300301103323023
64131430350223421
7264434645206036
oct35104645042205
97071687131884
102002102011013
117020a5432875
1228402bab4b71
13116a49ba7680
146cc8bb00a8d
153712c7e0a0d
hex1d226944485

2002102011013 has 4 divisors (see below), whose sum is σ = 2156109858028. Its totient is φ = 1848094164000.

The previous prime is 2002102011011. The next prime is 2002102011037. The reversal of 2002102011013 is 3101102012002.

It is a semiprime because it is the product of two primes.

It can be written as a sum of positive squares in 2 ways, for example, as 910196137764 + 1091905873249 = 954042^2 + 1044943^2 .

It is a cyclic number.

It is not a de Polignac number, because 2002102011013 - 21 = 2002102011011 is a prime.

It is a Harshad number since it is a multiple of its sum of digits (13), and also a Moran number because the ratio is a prime number: 154007847001 = 2002102011013 / (2 + 0 + 0 + 2 + 1 + 0 + 2 + 0 + 1 + 1 + 0 + 1 + 3).

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 2002102010984 and 2002102011002.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (2002102011011) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 77003923488 + ... + 77003923513.

It is an arithmetic number, because the mean of its divisors is an integer number (539027464507).

Almost surely, 22002102011013 is an apocalyptic number.

It is an amenable number.

2002102011013 is a deficient number, since it is larger than the sum of its proper divisors (154007847015).

2002102011013 is a wasteful number, since it uses less digits than its factorization.

2002102011013 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 154007847014.

The product of its (nonzero) digits is 24, while the sum is 13.

Adding to 2002102011013 its reverse (3101102012002), we get a palindrome (5103204023015).

The spelling of 2002102011013 in words is "two trillion, two billion, one hundred two million, eleven thousand, thirteen".

Divisors: 1 13 154007847001 2002102011013