Search a number
-
+
200210210131 = 281712491851
BaseRepresentation
bin1011101001110101110…
…1010101110101010011
3201010202222211110120211
42322131131111311103
511240012303211011
6231550355344551
720315252464351
oct2723535256523
9633688743524
10200210210131
11779aa498188
1232975bb2157
1315b58a3c879
149993da07d1
15531bb48b21
hex2e9d755d53

200210210131 has 4 divisors (see below), whose sum is σ = 200922702264. Its totient is φ = 199497718000.

The previous prime is 200210210099. The next prime is 200210210141. The reversal of 200210210131 is 131012012002.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 200210210131 - 25 = 200210210099 is a prime.

It is a super-2 number, since 2×2002102101312 (a number of 23 digits) contains 22 as substring.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (200210210141) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 356245645 + ... + 356246206.

It is an arithmetic number, because the mean of its divisors is an integer number (50230675566).

Almost surely, 2200210210131 is an apocalyptic number.

200210210131 is a deficient number, since it is larger than the sum of its proper divisors (712492133).

200210210131 is an equidigital number, since it uses as much as digits as its factorization.

200210210131 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 712492132.

The product of its (nonzero) digits is 24, while the sum is 13.

Adding to 200210210131 its reverse (131012012002), we get a palindrome (331222222133).

The spelling of 200210210131 in words is "two hundred billion, two hundred ten million, two hundred ten thousand, one hundred thirty-one".

Divisors: 1 281 712491851 200210210131