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200210211011 = 832412171217
BaseRepresentation
bin1011101001110101110…
…1010110000011000011
3201010202222211111210102
42322131131112003003
511240012303223021
6231550355353015
720315252500046
oct2723535260303
9633688744712
10200210211011
11779aa498908
1232975bb276b
1315b58a400a5
149993da0c5d
15531bb4900b
hex2e9d7560c3

200210211011 has 4 divisors (see below), whose sum is σ = 202622382312. Its totient is φ = 197798039712.

The previous prime is 200210210999. The next prime is 200210211031. The reversal of 200210211011 is 110112012002.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 200210211011 - 222 = 200206016707 is a prime.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 200210210983 and 200210211001.

It is not an unprimeable number, because it can be changed into a prime (200210211031) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 1206085526 + ... + 1206085691.

It is an arithmetic number, because the mean of its divisors is an integer number (50655595578).

Almost surely, 2200210211011 is an apocalyptic number.

200210211011 is a deficient number, since it is larger than the sum of its proper divisors (2412171301).

200210211011 is an equidigital number, since it uses as much as digits as its factorization.

200210211011 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 2412171300.

The product of its (nonzero) digits is 8, while the sum is 11.

Adding to 200210211011 its reverse (110112012002), we get a palindrome (310322223013).

The spelling of 200210211011 in words is "two hundred billion, two hundred ten million, two hundred eleven thousand, eleven".

Divisors: 1 83 2412171217 200210211011