Base | Representation |
---|---|
bin | 11101001000100111000… |
… | …100010011110101110101 |
3 | 21002101210111120011211021 |
4 | 131020213010103311311 |
5 | 230300310202414310 |
6 | 4131431241541141 |
7 | 264435104630122 |
oct | 35104704236565 |
9 | 7071714504737 |
10 | 2002110201205 |
11 | 7020aa017224 |
12 | 2840327a47b1 |
13 | 116a4b7b453a |
14 | 6cc8cc33749 |
15 | 3712d3ac5da |
hex | 1d227113d75 |
2002110201205 has 16 divisors (see below), whose sum is σ = 2418563063808. Its totient is φ = 1591002000000.
The previous prime is 2002110201193. The next prime is 2002110201227. The reversal of 2002110201205 is 5021020112002.
It is a happy number.
It is not a de Polignac number, because 2002110201205 - 235 = 1967750462837 is a prime.
It is a super-3 number, since 3×20021102012053 (a number of 38 digits) contains 333 as substring.
It is a Duffinian number.
It is a congruent number.
It is an unprimeable number.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 18701580 + ... + 18808330.
It is an arithmetic number, because the mean of its divisors is an integer number (151160191488).
Almost surely, 22002110201205 is an apocalyptic number.
It is an amenable number.
2002110201205 is a deficient number, since it is larger than the sum of its proper divisors (416452862603).
2002110201205 is a wasteful number, since it uses less digits than its factorization.
2002110201205 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 131748.
The product of its (nonzero) digits is 80, while the sum is 16.
Adding to 2002110201205 its reverse (5021020112002), we get a palindrome (7023130313207).
The spelling of 2002110201205 in words is "two trillion, two billion, one hundred ten million, two hundred one thousand, two hundred five".
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