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2002111423 = 13154008571
BaseRepresentation
bin111011101010101…
…1100101110111111
312011112022210112221
41313111130232333
513100020031143
6530400110211
7100420444354
oct16725345677
95145283487
102002111423
11938159a44
1247a605367
1325ba36420
1414dc8862b
15bab7d2ed
hex7755cbbf

2002111423 has 4 divisors (see below), whose sum is σ = 2156120008. Its totient is φ = 1848102840.

The previous prime is 2002111417. The next prime is 2002111427. The reversal of 2002111423 is 3241112002.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 2002111423 - 29 = 2002110911 is a prime.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 2002111397 and 2002111406.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (2002111427) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 77004273 + ... + 77004298.

It is an arithmetic number, because the mean of its divisors is an integer number (539030002).

Almost surely, 22002111423 is an apocalyptic number.

2002111423 is a deficient number, since it is larger than the sum of its proper divisors (154008585).

2002111423 is a wasteful number, since it uses less digits than its factorization.

2002111423 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 154008584.

The product of its (nonzero) digits is 96, while the sum is 16.

The square root of 2002111423 is about 44744.9597496746. The cubic root of 2002111423 is about 1260.3642650095.

Adding to 2002111423 its reverse (3241112002), we get a palindrome (5243223425).

The spelling of 2002111423 in words is "two billion, two million, one hundred eleven thousand, four hundred twenty-three".

Divisors: 1 13 154008571 2002111423