Base | Representation |
---|---|
bin | 1001000110101100001110… |
… | …11101001110001111110001 |
3 | 2121212222222221100022222011 |
4 | 10203112013131032033301 |
5 | 10111011220434320340 |
6 | 110325323501042521 |
7 | 4134322616604610 |
oct | 443260735161761 |
9 | 77788887308864 |
10 | 20021115151345 |
11 | 64199a860a840 |
12 | 22b4286b56441 |
13 | b22ca1a15829 |
14 | 4d30546a7877 |
15 | 24abdd97c0ea |
hex | 12358774e3f1 |
20021115151345 has 64 divisors (see below), whose sum is σ = 30132750827520. Its totient is φ = 12406287628800.
The previous prime is 20021115151309. The next prime is 20021115151363. The reversal of 20021115151345 is 54315151112002.
It is a de Polignac number, because none of the positive numbers 2k-20021115151345 is a prime.
It is a super-4 number, since 4×200211151513454 (a number of 54 digits) contains 4444 as substring.
It is an unprimeable number.
It is a polite number, since it can be written in 63 ways as a sum of consecutive naturals, for example, 45584509 + ... + 46021621.
It is an arithmetic number, because the mean of its divisors is an integer number (470824231680).
Almost surely, 220021115151345 is an apocalyptic number.
It is an amenable number.
20021115151345 is a deficient number, since it is larger than the sum of its proper divisors (10111635676175).
20021115151345 is a wasteful number, since it uses less digits than its factorization.
20021115151345 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 437846.
The product of its (nonzero) digits is 6000, while the sum is 31.
Adding to 20021115151345 its reverse (54315151112002), we get a palindrome (74336266263347).
The spelling of 20021115151345 in words is "twenty trillion, twenty-one billion, one hundred fifteen million, one hundred fifty-one thousand, three hundred forty-five".
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