Base | Representation |
---|---|
bin | 11101001000100111001… |
… | …011001101111110010111 |
3 | 21002101210121222012000112 |
4 | 131020213023031332113 |
5 | 230300311133342213 |
6 | 4131431344433235 |
7 | 264435126212003 |
oct | 35104713157627 |
9 | 7071717865015 |
10 | 2002112012183 |
11 | 7021000438a8 |
12 | 28403331881b |
13 | 116a4bc9991a |
14 | 6cc8d185703 |
15 | 3712d618ea8 |
hex | 1d2272cdf97 |
2002112012183 has 2 divisors, whose sum is σ = 2002112012184. Its totient is φ = 2002112012182.
The previous prime is 2002112012171. The next prime is 2002112012237. The reversal of 2002112012183 is 3812102112002.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 2002112012183 - 216 = 2002111946647 is a prime.
It is a super-2 number, since 2×20021120121832 (a number of 25 digits) contains 22 as substring.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (2002112012083) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1001056006091 + 1001056006092.
It is an arithmetic number, because the mean of its divisors is an integer number (1001056006092).
Almost surely, 22002112012183 is an apocalyptic number.
2002112012183 is a deficient number, since it is larger than the sum of its proper divisors (1).
2002112012183 is an equidigital number, since it uses as much as digits as its factorization.
2002112012183 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 384, while the sum is 23.
Adding to 2002112012183 its reverse (3812102112002), we get a palindrome (5814214124185).
The spelling of 2002112012183 in words is "two trillion, two billion, one hundred twelve million, twelve thousand, one hundred eighty-three".
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