Base | Representation |
---|---|
bin | 11101001000100111001… |
… | …011111110010010110111 |
3 | 21002101210122100020111220 |
4 | 131020213023332102313 |
5 | 230300311211210403 |
6 | 4131431353001423 |
7 | 264435130665015 |
oct | 35104713762267 |
9 | 7071718306456 |
10 | 2002112210103 |
11 | 702100169575 |
12 | 2840333b3273 |
13 | 116a4c038a35 |
14 | 6cc8d1d78b5 |
15 | 3712d657953 |
hex | 1d2272fe4b7 |
2002112210103 has 8 divisors (see below), whose sum is σ = 2785547422848. Its totient is φ = 1276709235384.
The previous prime is 2002112210099. The next prime is 2002112210141. The reversal of 2002112210103 is 3010122112002.
It is a sphenic number, since it is the product of 3 distinct primes.
It is not a de Polignac number, because 2002112210103 - 22 = 2002112210099 is a prime.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (2002112210173) by changing a digit.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 14508059425 + ... + 14508059562.
It is an arithmetic number, because the mean of its divisors is an integer number (348193427856).
Almost surely, 22002112210103 is an apocalyptic number.
2002112210103 is a gapful number since it is divisible by the number (23) formed by its first and last digit.
2002112210103 is a deficient number, since it is larger than the sum of its proper divisors (783435212745).
2002112210103 is a wasteful number, since it uses less digits than its factorization.
2002112210103 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 29016119013.
The product of its (nonzero) digits is 48, while the sum is 15.
Adding to 2002112210103 its reverse (3010122112002), we get a palindrome (5012234322105).
The spelling of 2002112210103 in words is "two trillion, two billion, one hundred twelve million, two hundred ten thousand, one hundred three".
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