Base | Representation |
---|---|
bin | 10010101001010110… |
… | …100110001110101101 |
3 | 1220200022022102020021 |
4 | 102221112212032231 |
5 | 312000403024240 |
6 | 13110402322141 |
7 | 1306066621453 |
oct | 225126461655 |
9 | 56608272207 |
10 | 20021142445 |
11 | 854445a717 |
12 | 3a69059351 |
13 | 1b70b9b065 |
14 | d7d02a9d3 |
15 | 7c2a4554a |
hex | 4a95a63ad |
20021142445 has 4 divisors (see below), whose sum is σ = 24025370940. Its totient is φ = 16016913952.
The previous prime is 20021142347. The next prime is 20021142521. The reversal of 20021142445 is 54424112002.
It is a semiprime because it is the product of two primes.
It can be written as a sum of positive squares in 2 ways, for example, as 2890782756 + 17130359689 = 53766^2 + 130883^2 .
It is a cyclic number.
It is not a de Polignac number, because 20021142445 - 213 = 20021134253 is a prime.
It is a super-2 number, since 2×200211424452 (a number of 21 digits) contains 22 as substring.
It is a congruent number.
It is an unprimeable number.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 2002114240 + ... + 2002114249.
It is an arithmetic number, because the mean of its divisors is an integer number (6006342735).
Almost surely, 220021142445 is an apocalyptic number.
It is an amenable number.
20021142445 is a deficient number, since it is larger than the sum of its proper divisors (4004228495).
20021142445 is an equidigital number, since it uses as much as digits as its factorization.
20021142445 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 4004228494.
The product of its (nonzero) digits is 2560, while the sum is 25.
Adding to 20021142445 its reverse (54424112002), we get a palindrome (74445254447).
The spelling of 20021142445 in words is "twenty billion, twenty-one million, one hundred forty-two thousand, four hundred forty-five".
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