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20021142445 = 54004228489
BaseRepresentation
bin10010101001010110…
…100110001110101101
31220200022022102020021
4102221112212032231
5312000403024240
613110402322141
71306066621453
oct225126461655
956608272207
1020021142445
11854445a717
123a69059351
131b70b9b065
14d7d02a9d3
157c2a4554a
hex4a95a63ad

20021142445 has 4 divisors (see below), whose sum is σ = 24025370940. Its totient is φ = 16016913952.

The previous prime is 20021142347. The next prime is 20021142521. The reversal of 20021142445 is 54424112002.

It is a semiprime because it is the product of two primes.

It can be written as a sum of positive squares in 2 ways, for example, as 2890782756 + 17130359689 = 53766^2 + 130883^2 .

It is a cyclic number.

It is not a de Polignac number, because 20021142445 - 213 = 20021134253 is a prime.

It is a super-2 number, since 2×200211424452 (a number of 21 digits) contains 22 as substring.

It is a congruent number.

It is an unprimeable number.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 2002114240 + ... + 2002114249.

It is an arithmetic number, because the mean of its divisors is an integer number (6006342735).

Almost surely, 220021142445 is an apocalyptic number.

It is an amenable number.

20021142445 is a deficient number, since it is larger than the sum of its proper divisors (4004228495).

20021142445 is an equidigital number, since it uses as much as digits as its factorization.

20021142445 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 4004228494.

The product of its (nonzero) digits is 2560, while the sum is 25.

Adding to 20021142445 its reverse (54424112002), we get a palindrome (74445254447).

The spelling of 20021142445 in words is "twenty billion, twenty-one million, one hundred forty-two thousand, four hundred forty-five".

Divisors: 1 5 4004228489 20021142445