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2002121341 = 11182011031
BaseRepresentation
bin111011101010101…
…1111001001111101
312011112100022011021
41313111133021331
513100020340331
6530400224141
7100420515313
oct16725371175
95145308137
102002121341
11938166440
1247a60b051
1325ba3aaac
1414dc8c0b3
15bab81211
hex7755f27d

2002121341 has 4 divisors (see below), whose sum is σ = 2184132384. Its totient is φ = 1820110300.

The previous prime is 2002121309. The next prime is 2002121351. The reversal of 2002121341 is 1431212002.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 2002121341 - 25 = 2002121309 is a prime.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (2002121351) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 91005505 + ... + 91005526.

It is an arithmetic number, because the mean of its divisors is an integer number (546033096).

Almost surely, 22002121341 is an apocalyptic number.

It is an amenable number.

2002121341 is a deficient number, since it is larger than the sum of its proper divisors (182011043).

2002121341 is a wasteful number, since it uses less digits than its factorization.

2002121341 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 182011042.

The product of its (nonzero) digits is 96, while the sum is 16.

The square root of 2002121341 is about 44745.0705776625. The cubic root of 2002121341 is about 1260.3663461911.

Adding to 2002121341 its reverse (1431212002), we get a palindrome (3433333343).

The spelling of 2002121341 in words is "two billion, two million, one hundred twenty-one thousand, three hundred forty-one".

Divisors: 1 11 182011031 2002121341