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20021313401 = 23870491887
BaseRepresentation
bin10010101001010111…
…001111111101111001
31220200022122002201222
4102221113033331321
5312000424012101
613110410121425
71306101233045
oct225127177571
956608562658
1020021313401
118544567101
123a69120275
131b70c2ab0b
14d7d073025
157c2a7b01b
hex4a95cff79

20021313401 has 4 divisors (see below), whose sum is σ = 20891805312. Its totient is φ = 19150821492.

The previous prime is 20021313379. The next prime is 20021313407. The reversal of 20021313401 is 10431312002.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 20021313401 - 214 = 20021297017 is a prime.

It is a Duffinian number.

It is a Curzon number.

It is a self number, because there is not a number n which added to its sum of digits gives 20021313401.

It is not an unprimeable number, because it can be changed into a prime (20021313407) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 435245921 + ... + 435245966.

It is an arithmetic number, because the mean of its divisors is an integer number (5222951328).

Almost surely, 220021313401 is an apocalyptic number.

It is an amenable number.

20021313401 is a deficient number, since it is larger than the sum of its proper divisors (870491911).

20021313401 is an equidigital number, since it uses as much as digits as its factorization.

20021313401 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 870491910.

The product of its (nonzero) digits is 144, while the sum is 17.

Adding to 20021313401 its reverse (10431312002), we get a palindrome (30452625403).

The spelling of 20021313401 in words is "twenty billion, twenty-one million, three hundred thirteen thousand, four hundred one".

Divisors: 1 23 870491887 20021313401