Base | Representation |
---|---|
bin | 11101001000101000011… |
… | …011011111010001001111 |
3 | 21002101212002120020201012 |
4 | 131020220123133101033 |
5 | 230300332030221133 |
6 | 4131433415435435 |
7 | 264435503111666 |
oct | 35105033372117 |
9 | 7071762506635 |
10 | 2002133054543 |
11 | 702110a06286 |
12 | 28403a385b7b |
13 | 116a5345661b |
14 | 6cc91ca1ddd |
15 | 371303c3b48 |
hex | 1d2286df44f |
2002133054543 has 4 divisors (see below), whose sum is σ = 2089182317808. Its totient is φ = 1915083791280.
The previous prime is 2002133054521. The next prime is 2002133054599. The reversal of 2002133054543 is 3454503312002.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 2002133054543 - 26 = 2002133054479 is a prime.
It is a Duffinian number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (2002133054743) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 43524631598 + ... + 43524631643.
It is an arithmetic number, because the mean of its divisors is an integer number (522295579452).
Almost surely, 22002133054543 is an apocalyptic number.
2002133054543 is a gapful number since it is divisible by the number (23) formed by its first and last digit.
2002133054543 is a deficient number, since it is larger than the sum of its proper divisors (87049263265).
2002133054543 is an equidigital number, since it uses as much as digits as its factorization.
2002133054543 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 87049263264.
The product of its (nonzero) digits is 43200, while the sum is 32.
Adding to 2002133054543 its reverse (3454503312002), we get a palindrome (5456636366545).
The spelling of 2002133054543 in words is "two trillion, two billion, one hundred thirty-three million, fifty-four thousand, five hundred forty-three".
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