Search a number
-
+
20022001313101 = 56513543089951
BaseRepresentation
bin1001000110101101111000…
…10001101010010101001101
32121220002021200211000100221
410203112330101222111031
510111020024314004401
6110325551434351341
74134353600056564
oct443267421522515
977802250730327
1020022001313101
11641a312850227
1222b449388b551
13b230b34a55b8
144d30da260bdb
1524ac416737a1
hex1235bc46a54d

20022001313101 has 4 divisors (see below), whose sum is σ = 20025544408704. Its totient is φ = 20018458217500.

The previous prime is 20022001313099. The next prime is 20022001313113. The reversal of 20022001313101 is 10131310022002.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 20022001313101 - 21 = 20022001313099 is a prime.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (20022001313191) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 1771539325 + ... + 1771550626.

It is an arithmetic number, because the mean of its divisors is an integer number (5006386102176).

Almost surely, 220022001313101 is an apocalyptic number.

It is an amenable number.

20022001313101 is a deficient number, since it is larger than the sum of its proper divisors (3543095603).

20022001313101 is an equidigital number, since it uses as much as digits as its factorization.

20022001313101 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 3543095602.

The product of its (nonzero) digits is 72, while the sum is 16.

Adding to 20022001313101 its reverse (10131310022002), we get a palindrome (30153311335103).

The spelling of 20022001313101 in words is "twenty trillion, twenty-two billion, one million, three hundred thirteen thousand, one hundred one".

Divisors: 1 5651 3543089951 20022001313101