Base | Representation |
---|---|
bin | 11101001000101100011… |
… | …011101010101101001011 |
3 | 21002102000202221010000122 |
4 | 131020230123222231023 |
5 | 230301001223212001 |
6 | 4131444215053455 |
7 | 264440246661143 |
oct | 35105433525513 |
9 | 7072022833018 |
10 | 2002200210251 |
11 | 70214590436a |
12 | 28405897128b |
13 | 116a6433a627 |
14 | 6cc9ab83923 |
15 | 3713623bb1b |
hex | 1d22c6eab4b |
2002200210251 has 2 divisors, whose sum is σ = 2002200210252. Its totient is φ = 2002200210250.
The previous prime is 2002200210247. The next prime is 2002200210253. The reversal of 2002200210251 is 1520120022002.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 2002200210251 - 22 = 2002200210247 is a prime.
Together with 2002200210253, it forms a pair of twin primes.
It is a Chen prime.
It is not a weakly prime, because it can be changed into another prime (2002200210253) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1001100105125 + 1001100105126.
It is an arithmetic number, because the mean of its divisors is an integer number (1001100105126).
Almost surely, 22002200210251 is an apocalyptic number.
2002200210251 is a deficient number, since it is larger than the sum of its proper divisors (1).
2002200210251 is an equidigital number, since it uses as much as digits as its factorization.
2002200210251 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 160, while the sum is 17.
Adding to 2002200210251 its reverse (1520120022002), we get a palindrome (3522320232253).
It can be divided in two parts, 20022002 and 10251, that multiplied together give a palindrome (205245542502).
The spelling of 2002200210251 in words is "two trillion, two billion, two hundred million, two hundred ten thousand, two hundred fifty-one".
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